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CDMA_MODULATION_DEMODULATION
- 复接入,B/W双用户使用直接扩频序列 % >>>multiple access b/w 2 users using DS CDMA % >>>format is : cdmamodem(user1,user2,snr_in_dbs) % >>>user1 and user2 are vectors and they should be of equal length % >>>e.g. user1=[1 0
cdma_training_080805
- 功能:CDMA调变 multiple access b/w 2 users using DS CDMA-multiple access b/w 2 users using DS CDMA format is : cdmamodem(user1,user2,snr_in_dbs) user1 and user2 are vectors and they should be of equal length
cdmamodem
- 2个用户的DS CDMA ,2个用户长度必须相等-multiple access b/w 2 users using DS CDMA user1 and user2 are vectors and they should be of equal length
ds_cdma
- DS-CDMA实现基本过程: <TRANSMITTING END>待传信息--NRZ变换(变成NRZ码)---调制(乘以sqrt(2*eb)*cos(2*w*t))----扩频(乘以m序列或其他伪随机码) ----信道中传输(有加性噪声)<DURING THE CHANNEL> ---解扩(乘以相同的m序列或其他伪随机码)---解调(乘以sqrt(2*eb)*cos(2*w*t))----比特判别(sum(i)>0-->1 sum(i)<0-