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DDA画直线实验一
- DDA直线画线算法，希望能用得上。是老师在课堂上要求的，希望对大家有用-DDA straight line drawing algorithm, hope to ebb and flow. The teachers in the classroom requirements, I hope useful for all
Bresenham&DDA
- 《计算机图形学》用DDA和Bresenham算法画直线-"Computer Graphics" with DDA and the Bresenham algorithm painting line
DDA
- DDA圆弧插补编程 用于数控中的 可实现在某一象限的圆弧插补
DDA
- c++程序，实现了数字图像处理 的 DDA划线，在一个图像里 根据要求画一条线。
DDA
- DDA算法的具体实现 在VC下实现
MFC-DDA
- 用mfc实现的dda画直线算法 dda你懂得-With mfc painting a straight line algorithm to achieve the dda
DDA
- 扫描线算法。有DDA 中点算法，以及圆的中点扫描算法-Scan line algorithm. There DDA midpoint algorithm, as well as the mid-point of circular scan algorithm
DDA
- DDA Line Drawing Algorithm
DDA
- 使用DDA画线算法实现基本图元绘制的程序-DDA line drawing algorithm used to achieve the basic elements of the process mapping
dda
- 用dda算法编程，画直线。通过mfc的环境下写程序-Dda algorithm with programming, drawing a straight line. Mfc environment through the writing process
DDA
- DDA画线算法，是计算机图形学原理及算法里的一种很简单的栅格数据的直线画法-DDA line drawing algorithm, computer graphics theory and algorithms inside a very simple straight-line drawing method of raster data
DDA
- 直线DDA算法。。包含思想和概述。计算机图形学的实验之一，可以画出直线，不用考虑斜率的变化。-DDA line algorithm. . Contains ideas and an overview. Computer Graphics of the experiment, one can draw a straight line, without regard to slope changes.
dda.c
- Implementaç ã o do Algoritmo de Line DDA, usando em no desenvolvimento de jogos em computaç ã o gráfica
DDA
- 实现计算机图形学DDA算法帮助您实现实验要求-DDA algorithm to achieve computer graphics to help you achieve the requirement of experiment
DDA
- 计算机图形学中的直线画法，DDA算法，对每一个步长的x所对应的y进行判断-Computer graphics line drawing, DDA algorithm, each step on the x-y corresponding to judge. . .
dda
- thuậ t toán dda, làm mã i cũ ng ko xong
DDA
- 在石根华源程序的基础上修改的windows界面的DDA计算程序-DDA windows interface computer program
DDA
- 基于DDA插补算法的2维直线插补源码,并绘制插补轨迹曲线.-DDA interpolation algorithm based on linear interpolation of 2-dimensional source, and draw the interpolation trajectory curve.
dda
- it contains the dda code
MFC画直线程序（DDA和Brensenham）
- DDA Bresenham, A brief code in MFC...................