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  1. lms3

    0下载:
  2. w=(randn(1,M)-randn(1,M))/100 d=zeros(1,M) u=zeros(1,M) u_out=zeros(1,e_max-M) f_out=zeros(1,e_max-M) X delayed input data vector Y measured signal W coefficient vector E enhanced signal clc N=30 f
  3. 所属分类:Communication-Mobile

    • 发布日期:2017-03-25
    • 文件大小:708
    • 提供者:venkat
  1. das3

    0下载:
  2. ecgbeat.m Author - Arun Kumar A , Santhom Computing Facility Email - aka.bhagya@gmail.com 03/07/09 Program to Calculate the beats of an ECG signal Uses Continuous Wavelet Transform Data file should be a csv file close all
  3. 所属分类:Communication-Mobile

    • 发布日期:2017-03-26
    • 文件大小:679
    • 提供者:dasu
  1. da4

    0下载:
  2. ecgbeat.m Author - Arun Kumar A , Santhom Computing Facility Email - aka.bhagya@gmail.com 03/07/09 Program to Calculate the beats of an ECG signal Uses Continuous Wavelet Transform Data file should be a csv file close all
  3. 所属分类:Communication-Mobile

    • 发布日期:2017-03-31
    • 文件大小:677
    • 提供者:dasu
  1. das1

    0下载:
  2. Removing all variables, functions, and MEX-files from memory, leaving the workspace empty. clear all Deleting all figures whose handles are not hidden. close all Deleting all figures including those with hidden handles. cl
  3. 所属分类:Communication-Mobile

    • 发布日期:2017-04-03
    • 文件大小:1570
    • 提供者:dasu
  1. routing99

    0下载:
  2. clc clear all close all Field Dimensions - x and y maximum (in meters) xm = 200 ym = 200 sink.x =0.25 * xm sink.y =0.875 * ym -clc clear all close all Field Dimensions - x and y maximum (in meters) xm = 200 y
  3. 所属分类:Communication-Mobile

    • 发布日期:2017-04-04
    • 文件大小:770
    • 提供者:Hemanth
  1. sureshaodv

    0下载:
  2. Code : AODV Routing. x=1:20 s1=x(1) d1=x(20) clc A=randint(20) Making matrix all diagonals=0 and A(i,j)=A(j,i),i.e. A(1,4)=a(4,1), A(6,7)=A(7,6) for i=1:20 for j=1:20 if i==j A(i,j)=0 else A(j,i)=A(i,j) en
  3. 所属分类:Communication-Mobile

    • 发布日期:2017-03-27
    • 文件大小:721
    • 提供者:Hemanth
  1. dijkstra

    0下载:
  2. clear all clc D=[0 6 inf inf 5 6 inf 5 inf 6 0 9 inf inf 9 inf 3 inf inf 9 0 7 inf inf 4 inf inf inf inf 7 0 6 4 6 inf 3 5 inf inf 6 0 5 inf inf 4 6 9 inf 4 5 0 5 inf inf inf inf 4 6 inf 5 0 inf inf 5 3 inf inf inf inf inf 0
  3. 所属分类:Communication-Mobile

    • 发布日期:2017-03-21
    • 文件大小:581
    • 提供者:Hemanth
  1. routing

    0下载:
  2. clc clear n=input( Total node= ) if n > 6 error( not <6 ) end alphabets= char(65:1:65+n) adj=zeros(n,n) for p=1:n for q=1:n adj(p,q)=input([ Enter Weight between [ ,alphabets(p), ] , [ ,alphabets(q), ] = ]) end e
  3. 所属分类:Communication-Mobile

    • 发布日期:2017-03-31
    • 文件大小:530
    • 提供者:Hemanth
  1. cmda2000

    0下载:
  2. matlab写的cdma2000物理层调制解调仿真 clear clc SNR=15 Len_PN=16 Len_Data=10 Len_Chip=Len_PN*Len_Data -matlab cdma2000 program clear clc SNR=15 Len_PN=16 Len_Data=10 Len_Chip=Len_PN*Len_Data
  3. 所属分类:Communication-Mobile

    • 发布日期:2017-03-29
    • 文件大小:1131
    • 提供者:hualongfei
  1. new1

    0下载:
  2. clc clear number of subbands K = 32 oversampling ratio O = 2 decimation rate D = K/O number of taps per polyphase component P = 3 total prototype filter length is L = D*P prototype filter-clc clear number of
  3. 所属分类:3G develop

    • 发布日期:2017-11-05
    • 文件大小:1568
    • 提供者:ylt_9811115
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