游戏规则：将总数为M的纸牌（是N的倍数），任意的划分成成数目不等的N堆，然后经过下列规则的移动，使得每堆牌的数目相等：1.要向第i堆牌移动牌，只能从i+1堆或i-1堆中取得；2.第一堆牌只能从第二堆牌中取得；3.第N堆牌只能从第N-1堆牌中取得。 算法要求：求解均分时的最小移动次数-Rules of the game: the total M of the card (which is a multiple of N), divided into any number ranging fro

简单的分牌算法，java类，实现随即分成四堆牌-Simple scoreboard algorithm, java class, then divided into four reactor licensing

任给N堆石子,两人(游戏者与计算机)轮流从任一堆中任取,计算机先取,取最后一颗石子胜-Any stones to the N Reactor, the two (the game with the computer) take turns in a pile from any from any computer to check, take the last stone wins a

How to programming with ACE Reactor framework.