搜索资源列表
15-05-0114-00-004a-ieee802-15-4a-channel-model-mat
- WPAN国际标准IEEE802.15发布的信道模型的MATLAB源码。包括几种室内和室外模型。都是基于改进的SV模型。应用在短距离超宽带UWB无线通信中。 -WPAN IEEE802.15 international standards issued by the channel model of MATLAB source. Several, including indoor and outdoor models. Improvements are based on the SV mode
BCH(15-7-5)
- BCH(15,7,5)纠错译码的MATLAB实现
IEEE802.15.3aUWB
- IEEE 802.15.3a UWB信道模型仿真，
四种方法求解15阶线性方程组
- 采用Cramer算法、Gauss列主元、Gauss全主元、Doolittle算法等四种方法求解15阶线性方程组的C++代码
IEEE 802.15.4 物理层仿真程序
- 该程序为IEEE 802.15.4物理层仿真程序。工作频段为2.4GHz,信道模型为AWGN，仿真不同SNR情况下的BER。-This is a matlab programme of IEEE 802.15.4 which simulate the ber in different SNR values.The channel model is AWGN.
15数码问题的3种算法(算法和具体代码)
- 15数码问题的3种算法(算法和具体代码) 解决15数码问题的3种算法，分别是深度，宽度，以及A*算法。c语言编写，VC下都通过运行。,15 digital issues three kinds of algorithm (algorithm and the specific code) to solve the problem of 15 digital three kinds of algorithms, respectively, are the depth, width, and th
60ghz-channel-model-matlab
- 802.15.3c中60ghz信道模型 包含多种场景 -802.15.3c channel model about 60ghz
CRC16
- CRC16 calculator for IEEE 802.15.4. Can download and try it.
15-07-0648-00-003c-channel-model-matlab-code-relea
- this code can simulate the channel model for IEEE 802.15.3c.-802.15.3c channel model including LOS and NLOS model
rs_code
- rs(15,11)编码实现，对于学习RS编码原理的人员可以作为一个例子学习，也可以应用于相应的系统中。 -rs (15,11) encoding the realization of the principle of learning personnel RS coding can be used as an example of learning, can also be applied to the corresponding system.
OQPSK-Demodulator-projekt
- OQPSK Demodulation Project in Matlab. OQPSK means offset quadrature phase shift keying. an important modulation scheme in IEEE 802.15.4
Practical-15-cases-of-Matlab
- 包含Matlab十五个常用的小例子哦，菜鸟新手练手的好-Matlab contains a small example of 15 commonly used Oh, rookie novice practicing good hand Dongdong
matlab11-15
- 精通matlab7这本书的例程，11-15部分-Proficient matlab7 this book routine, 11-Part 15
IEEE802.15.4a
- IEEE802.15.4a 的matlab模型-IEEE802.15.4a based in matlab
n-puzzle
- n-puzzle (8-puzzle, 15-puzzle, 24-puzzle) solution using A* algorithm. i have used 2 pass for reducing memory consumption by half. i will post it also on my blog http://rooparam.blogspot.com-n-puzzle (8-puzzle, 15-puzzle, 24-puzzle) solution using A*
PerformanceEvaluationIEEE802.15.4PHY_Matlab
- paper on 802.15.4 simulation
（15，11）汉明码---matlab仿真---BPSK调制
- （15，11）汉明码matlab仿真，信息位11个，4位监督位
ieee802.15.4 by matlab
- modeling ieee802.15.4 (mac and phy layer)in matlab
HM-15.0-dev
- HM-15.0 HEVC平台,主要用于高清视频的压缩编码 联合开发(HM-15.0 HEVC platform, mainly used for high definition video compression coding joint development)
15数码求解
- 15数码问题的求解思路，给定一个最小的h*，递归地增加h*的值，每次加一，直到找到最优解。(Given a minimum h*, the solution of the 15-digit problem increases the value of h* recursively, one at a time, until the optimal solution is found.)