搜索资源列表
ustc2
- robocup中国科技大学2队的代码,守门员代码写得很好,总体写得也是相当不错的-RoboCup China Science and Technology University 2 team code, code written in a very good goalkeeper, on the whole is written in fairly good
haffmantree
- ADT HuffmanTree{ 数据对象:D={ai| ai∈CharSet,i=1,2,……,n, n≥0} 数据关系:R={< ai-1, ai > ai-1, ai∈D, ai-1基本操作P: HuffmanTree() 构造函数 ~ HuffmanTree() 析构函数 Initialization(int WeightNum) 操作结果:构造哈夫曼树。 Encoder() 初始条件:哈夫曼树已存在或者哈夫曼树已存到文件中。
AI
- 导弹拦截飞机的源代码,通过算出两者间的距离,时间差,速度,利用拦截算法算出相关数值,从而实现-Aircraft missiles to intercept the source code, through the calculated distance between the two, the time difference, speed, calculated using the relevant numerical algorithm block in order to achieve
3_2Niv_Comp
- C’est avec un grand plaisir que je remercie M Franç ois Costa, M Jean Luc Schanen et M Faouzi Ben Ammar qui ont accepté de faire partie de mon jury de thèse. Des remerciements aussi chaleureux vont à mes collègues du CEGELY avec qui j’ai pa
CPPBuilder
- C++Builder中国象棋研发,里面含有人工智能象棋研发的基本教程,以及各种算法,搜索算法-C++ Builder development of Chinese chess, chess AI R & D which contains the basic tutorials, and a variety of algorithms, search algorithms
c3
- 组合问题 问题描述:找出从自然数1,2,…,n中任取r个数的所有组合。 采用回溯法找问题的解,将找到的组合以从小到大顺序存于a[0],a[1],…,a[r-1]中,组合的元素满足以下性质: (1) a[i+1]>a,后一个数字比前一个大; (2) a-i<=n-r+1。 -Combinatorial problems Problem Descr iption: Find out from the natural numbers 1,2, ..., n r t
ecgsyn
- ECG waveform generator for MATLAB [s, ipeaks] = ecgsyn(sfecg,N,Anoise,hrmean,hrstd,lfhfratio,sfint,ti,ai,bi) Produces synthetic ECG with the following outputs: s: ECG (mV) ipeaks: labels for PQRST peaks: P(1), Q(2), R(3), S(4)
Identifi-cation-of-Inducti-on-Motors
- 为减小感应电机转动惯量对机械特性的影响 ,基于最小二乘法 ,引入开关控制器 ,构建了一种新 型的最小二乘参数辨识器 -To reduce the infl uence tha t the vari ai on of the inertiato the mechani cal characteristics of induction moto r , a new identifier based on the Recursive L eat Square salgorithm is propo
