将一个周期曲柄的转角如从0°到360°分成100个点，令dθ ω1dt；Medθ是转过 dθ角度等效力矩做的功，右边d()为动能的增量。编制相应的程序，即可求出每个位置对应的等效力矩Me，从而可求出驱动力矩M1-100 points, let dθ ω1dt Medθ is the work done by dθ angle equivalent moment, the right d () is the increment of kinetic energy. The preparati

关于MED的程序源码，经本人验证，可以在matlab上运行(On the MED program source code, I verify, can run on matlab)