硬币找钱问题的解决方案，时间复杂度小，方法十分方便-Coin find money solution to the problem

有n种不同面值的硬币，各硬币面值存于数组T[1:n] 现用这些面值的钱来找钱；各面值的个数存在数组Coins[1:n]中。 对于给定的1<=n<=10，硬币面值数组、各面值的个数及钱数m，0<=m<=2001，编程计算找钱m的最少硬币数。 -There are n different denominations of coins, each coin denomination stored in the array T [1: n] current face v

硬币找零算法（动态规划）：有一堆不同面值的硬币，需要找到一个硬币数最少的组合来组成某一个数值。-Coin change algorithm (dynamic programming): There are a bunch of different denominations of coins, need to find a combination of the number of coins to form at least one value.