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计算机操作系统原理与实现中的重要实验,关于哲学家进餐的问题-computer operating system Theory and the important experiments on the dining philosophers problem
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哲学家进餐问题,进程是独立参与分配资源的最小单位,在有线程的OS中,线程是运行的最小单位,
课堂所述进程之间的同步与互斥,实际上是属于不同进程的线程间的同步与互斥,当
然,属于同一进程的不同线程一样存在同步与互斥,其控制同步与互斥的原理跟进程
是一样的-dining philosophers problem, the process is independent participation in the allocation of resources as the smallest
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经典进程同步和互斥另类WINDOWS解法.定义信号量机制在WINDOWS下完成哲学家进餐问题.-classical process synchronization and mutex WINDOWS alternative solution. Volume definition signal mechanism in Windows complete the dining philosophers problem.
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在Linux环境下,使用共享外部变量的方式,实现哲学家进餐问题-the Linux environment, the use of shared external variables, to achieve the Dining Philosophers Problem
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在STM32上编写多任务实时操作系统,同时运行6个任务,通过发送和接收信号量机制,解决哲学家就餐问题,通过板上按键代表哲学家的就餐请求,板上LED灯表示就餐成功或者未果,同时在晶体数码管上显示就餐申请时间。-STM32 to write multi-task in real-time operating system, run six tasks by sending and receiving semaphore mechanism to solve the dining philosophe
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C多线实现哲学家就餐问题-C multi-line to achieve the dining philosophers problem
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ucos-dining-philosopher.rar
ucos下的哲学家就餐问题(dining philosopher problems),采用信号量机制解决,有截图和感悟。dos界面文字演示(另有图形界面)。-ucos-dining-philosopher.rarucos under the dining philosophers problem (dining philosopher problems), using semaphore mechanism to resolve scr
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哲学家就餐问题C语言模拟,pthread库实现-The Dining Philosophers Problem C language simulation, pthread library implementation
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程序源代码:
/*
Item The Dining Philosophers Problem
具体要求
1) 5个哲学家,先吃饭,后思考。
2) 每个哲学家都需要吃9顿饭,思考9次,然后结束。
3)吃饭时间为3~12秒的随机时间
4)思考时间为7~19秒的随机时间
5)对取叉子和放叉子等临界资源的操作前后需要输出相关状态信息,包括哲学家的各种状态信息。要有足够的信息的输出要能证明哲学家之间吃饭不产生竞态。
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本程序是在Linux下面 实现了哲学家就餐问题。其中演示了会发生死锁和不会发生死锁的情况。-This program is implemented in the Linux following the Dining Philosophers Problem. Which demonstrates the deadlock and does not happen will happen deadlock situation.
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这个程序可以演示关于哲学家就餐的问题,对于理解线程的相互等待有很好的作用-This procedure can be demonstrated on the Dining Philosophers problem, each thread to wait for understanding the role of good
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哲学家就餐问题的解决,操作系统中线程与并发的问题-Solution to the dining philosophers problem
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哲学家就餐问题 实现5个哲学家5支筷子的就餐问题涉及到AND型信号量,线程的阻塞唤醒切换功能-Dining philosophers problem to achieve five dining philosophers five chopsticks issues related to the AND-type semaphore, blocking thread switching wake
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多线程解决哲学家就餐问题,实现进程与线程间的同步。-Multi-threading to solve the dining philosophers problem, to achieve synchronization between processes and threads.
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通过实现哲学家进餐问题的同步深入了解和掌握进程同步和互斥的原理-Through the dining philosophers problem of synchronization-depth understanding and mastery of process synchronization and mutual exclusion principle
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操作系统之哲学家就餐问题的算法实现,利用java开发语言-The operating system of the dining philosophers problem algorithm
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哲学家就餐问题是一道十分经典的进程同步问题。该道题旨在解决当资源有限时(可能产生死锁),如何有效地避免死锁的问题。本实验选取“and”型信号量的解决办法,只有当哲学家具备同时拿到左右两只筷子的能力时,才能吃饭。否则,若则学家只能能够拿到一只筷子时,他只能放弃这只筷子,供其他可能需要这只筷子的哲学家使用。这样,只有哲学家左右两人均不进食时,该哲学家才有吃饭的权利。采取这种方法可以有效地避免死锁的产生。-The dining philosophers problem is a very classi
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关于哲学家进餐的问题,运用了mfc,有动态演示效果-About the Dining Philosophers problem, the use of mfc, dynamic demonstration effect。。
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操作系统中关于冲突的哲学家就餐问题的简单实现-Simple implementation of the operating system on the dining philosophers problem of conflict
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c++程序,利用信号量解决哲学家就餐问题,非常好用-c++ program using semaphores to solve the dining philosophers problem, very easy to use
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