资源列表
faceimagesbyrf
- 从老外文章里看到一种基于分类器的人脸检测方法，好不容易搞到这个人脸图像训练集和测试集，现在贡献出来，希望对做人脸检测的朋友有帮助（图像比较全，有彩色人脸图像）-from generals saw an article based on the classification of face detection method finally got the facial image training set and test set, now contribute, hope to the huma
200671920394993
- 第一个公开源码的游戏内存修改作弊程序！支持搜索过滤任意进程（核心进程除外）所在的内存中和搜索匹配的内容，并对内存值进行锁定、修改等功能！Win98或2000下测试通过。-first open-source memory of the game revised procedures for cheating! Search filter support arbitrary process (except for the core process) where the memory matching
HardUerofEngineer
- \"工程师硬件使用手册\"此书使你工作轻轻松松查询各种常用电子线路及电子元器件引脚符号!-"hardware engineers use manual," this book to make you work a light-hearted advice on various common electronic circuits and electronic devices yuan Symbol pieces pin!
pqbg
- 觉得要是不好一定要告诉我啊~~谢谢~~~说明自己看,我也不知道怎么说-feel bad if I must tell ah ~ ~ ~ ~ ~ Thank you stated your view, I do not know how that
procomm
- dos 系统下 isa内猫模块的测试程序-dos systems within isa cat module testing procedures
blackbutton_control
- A BLACK BUTTON CONTROL EVM:Visual c++ 6.0-EVM CONTROL : Visual c 6.0
avifil32DLL
- IF YOUR DESIGN A VIDEO SYSTEM YOU NEEDED IT （INCLUDE A AVIFIL32.DLL) It Fit VFW-IF YOUR VIDEO SYSTEM DESIGN A YOU NEEDED IT ( INCLUDE A AVIFIL32.DLL) It Kazaam VFW.
shudebianli
- 数据结构做的一个小程序 对二叉进行的遍历-data structure to do a small procedure on the two forks of the ergodic
shujujiegoudanlianbiao
- 输入一系列递减顺序的整数（100,50,40,30……），以0标志结束，将这些数作为data域逆序建立一个单链表；从键盘输入一个整数X，将X插入到此单链表中并保持单链表data域的值递增关系，输出此时单链表各结点data域的值；从键盘输入一个整数Y，若Y值在单链表中存在，则删除data域的值为Y的结点（注单链表中没有data域值相同的结点），并输出此时单链表各结点data域的值。-importation of a series of descending order of the integer
shujujiegoushunxuzhandeyingyong
- 初始化一个顺序栈，编制实现入栈一个元素和出栈一个元素的程序。-an initialization sequence stack, drawing up a stack elements and elements of a stack up procedures.
shunxubiaodeyiyong
- 4. 建立一个有序的顺序表（10，30，35，50，56，100，120），用折半查找方法在此表中查找任一整数，若找到则输出此整数在表中的位置序号，否则输出Not found.-4. Establish an orderly sequence (10,30,35,50,56,100,120) using binary search method in this table as a whole you, if the output is found in this round table pos
cyuyanshuzu
- 编程求出二维数组中的最大和最小元素的值及其位置。设二维数组如下： A={ { 3,13,7,9},{11,8,23,5},{6,34,16,4}}。 -programming calculated two-dimensional array of elements in the largest and smallest values and its location. Two-dimensional arrays located as follows : A = () (3,13,7,9