资源列表
TravelingSalesmanProblem
- 用便宜算法解决旅行商问题，附测试用例和报告-Cheap algorithm used to solve traveling salesman problem, with test cases and reporting
ArithmeticExpressionEvaluation
- 算术表达式求值 从键盘读入一个合法的算术表达式，输出正确的结果，并显示输入序列和栈的变化过程。-Arithmetic Expression Evaluation Reading from the keyboard into a legitimate expression of the arithmetic, the output correct results, and display the input sequence and stack the process of change.
ercha
- 利用C语言写的二叉树应用关于表达式处理源代码-Using C language to write applications on the expression of the binary tree deal with source code
datrie_cvs20061001.tar
- This an implementation of double-array structure for representing trie, as proposed by Junichi Aoe [1]. Trie is a kind of digital search tree, an efficient indexing method with O(1) time complexity for searching. Comparably as efficient as h
Sudu
- 使用MFC写的一个解数独的程序，主要使用了类CNineGong及CCell,原理回溯法测试填入的数字是否合理，做了些优化，速度比以前快许多-Use MFC to write a single procedure itself, the main use of the category CNineGong and CCell, the principle of backtracking fill in the number of tests is reasonable, to do some op
heap
- 程序用VC编写，完成插入、删除、调整堆、输出堆元素的功能 ①输入的形式和输入值的范围：输入元素个数与数据。 ②输出的形式：排列输出。 ③ 程序所能达到的功能：插入、删除、调整、输出。 -Heap and
GAs
- 使用遗传算法求一个多项式函数在区间[0，37]之间的极大值，编程环境采用Matlab6.0。-The use of genetic algorithm for a polynomial function in the interval [0,37] between the maximum value, the use of programming environment Matlab6.0.
node
- 自己编写的解八数码问题的简单算法，用c++实现-I have written eight digital solution of a simple algorithm for the problem.
Hamilton
- 利用回溯法求解hamilton回路的算法-Use of backtracking algorithms for solving circuit hamilton
perm
- 利用回溯法求解背包问题和全排列的算法，用c++实现。-The use of retrospective method knapsack problem and the whole array of algorithms, using c++ realize.
package
- 用动态规划来解背包问题,很不错的算法，可以学习学习-Using dynamic programming to solve knapsack problem, it is a good algorithm, you can learn
three-sample-of-Data-Structure
- 数据结构，一共有三个文件，多项式相加，二叉树几种操作，数组正负排序-Data structure, a total of three documents, the sum of polynomials, binary tree several operations to sort the array of plus or minus