文件名称:jiancehuiwen
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问题描述:对于给定的一个n个字符组成的字符串s,判断其是否为回文,设字符串s为:
S:”C1,C2,…….Ci,Ci+1,…..Cn”,则对于P=(n/2),字符串s满足如下条件。
若n为偶数,则有C1=Cn,C2=Cn-1,….,Cp-1=Cp+2,Cp=Cp+1
若n为奇数,则有C1=Cn,C2=Cn-1,….,Cp-1=Cp+3,Cp=Cp+2.
-The descr iption of the problem: given an n-character string s, to determine whether it is a palindrome, set up a string s is: S: C1, C2, .... of Ci, Ci+1, ..... of Cn " P = (n/2), the string s to meet the following conditions. If n is even, then C1 = Cn, C2 = Cn-1, ...., of Cp 1 = Cp+2 of, Cp = Cp+1 if n is odd, then C1 = Cn, C2 = Cn-1, .... Cp-1 = Cp+3, Cp = Cp+2.
S:”C1,C2,…….Ci,Ci+1,…..Cn”,则对于P=(n/2),字符串s满足如下条件。
若n为偶数,则有C1=Cn,C2=Cn-1,….,Cp-1=Cp+2,Cp=Cp+1
若n为奇数,则有C1=Cn,C2=Cn-1,….,Cp-1=Cp+3,Cp=Cp+2.
-The descr iption of the problem: given an n-character string s, to determine whether it is a palindrome, set up a string s is: S: C1, C2, .... of Ci, Ci+1, ..... of Cn " P = (n/2), the string s to meet the following conditions. If n is even, then C1 = Cn, C2 = Cn-1, ...., of Cp 1 = Cp+2 of, Cp = Cp+1 if n is odd, then C1 = Cn, C2 = Cn-1, .... Cp-1 = Cp+3, Cp = Cp+2.
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