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guohewenti
- 试运用深度优先搜索算法寻找过河问题的一个解决方案，题目叙述如下：猎人、狗、男人带着男孩1、男孩2，女人带着女孩1、女孩2，一共8个个体。一艘小船，一次只能过两个个体，狗和四个小孩不会划船。注意：（1）猎人不在，狗咬任何人；（2）男人不在，女人打男孩；（3）女人不在，男人打女孩。-Test the use of depth-first search algorithm to find a solution to cross the river problem, topics are describ
ah
- 本程序中定义了函数ave，其形参为结构指针变量ps。boy被定义为外部结构数组，因此在整个源程序中有效。在main函数中定义说明了结构指针变量ps，并把boy的首地址赋予它，使ps指向boy数组。然后以ps作实参调用函数ave。在函数ave中完成计算平均成绩和统计不及格人数的工作并输出结果。-This procedure defines a function in the ave, the shape parameters for the structure pointer variable p
di9ti
- 有N个小孩围成一圈并依次编号，教师指定从第M个小孩开始报数，报到第S个小孩即令其出列。然后从下一个孩子继续报数，数到第S个小孩又令其出列，如此直到所有的孩子都出列。求小孩出列的先后顺序。 -With N a child form a circle and turn number of teachers designated starting from the reported number of M a child, report the first S out of a child or ma
boy.wufanhuidian
- 可以实现鱼的抢球功能，根据鱼的位置自动定位鱼的轨迹-You can fish the ball function, automatic positioning of fish according to the position of the track fish
mygame
- C#制作的一个简单的竞技比赛的小游戏。男孩的女孩比赛，看谁先到。-Game C# produced a simple athletic competition. Boy Girl competition to see who first.
NormalDistribution
- FrameWork4.0平台下比较通用的位图生成-正太分布。(The FrameWork4.0 platform - bitmap generation more general distribution of teenage boy.)
Le?o magestoso 9desktop
- A five-year-old Indian boy gets lost on the streets of Calcutta, thousands of kilometers from home. He survives many challenges before being adopted by a couple in Australia. 25 years later, he sets out to find his lost family.A five-year-old Indian