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BosonNetSim
- BOSON NETSIM是目前最好的路由器模拟软件，说是路由模拟有些片面，因为它不仅可以模拟路由器，同时可以模拟交换机，当然像3550这样的它是不可能模拟出来的，但用它来准备NA及NP的考试，是再合适不过的了，甚至有些IE的实验，通过它的自定义网络拓扑功能都可以实现，可以说功能强大之极，其他的模拟器无可与之相匹，当然了，除了CISCO专门为IE准备的CIM，那个就不是我们要讨论的范围了。 由于BOSON的加密技术比较厉害，想要破解它非常不易，所以，要找它的破解过的最新版十分困难 。这里
Cenario
- Uma modelagem de um cenario basico para quem esta aprend o a usar open/gl na plataforma C++. Utilizando comandos basicos como setas direcionais e teclas especiais como home, end, page up e page down voce pode navegar por todo o ambiente 3D com muita
Form1
- konvertor na valuti napraven vo mvc-konvertor na valuti napraven vo mvc++
OP07_a
- The OP07 has very low input offset voltage (75 μV max for OP07E) which is obtained by trimming at the wafer stage. These low offset voltages generally eliminate any need for external nulling. The OP07 also features low input bias current (±4 nA
PKUACMreport
- 这是北京大学ACM在线POJ的一些重要题目的解题报告，其中在PPT中有详细的源码。一共100个左右。-This is the Peking University ACM online POJ some of the important topics of the problem-solving report, which are detailed in the PPT source. A total of about 100.
na
- 数值分析lab 数值分析lab-Numerical analysis lab numerical analysis lab numerical analysis lab
TT86
- TT86论坛辅助源码，绝对原创！可以一键登录，一键回帖！新人拿去研究吧-TT86 Forum auxiliary source, definitely original! Can be a key to log on, a key Replies! Research new it Na Qu
lista2
- O incentivo a vanç o tecnológico, assim como a consolidaç ã o das estruturas representa uma abertura para a melhoria do levantamento das variáveis envolvidas. Neste sentido, a expansã o dos mercados mundiais auxilia a preparaç
analysis
- This example will demonstrate the use of the FFT function to calculate\na 2D-FFT. Given that the data represents the width and the delay of two\nsignals this program calculates the 2D-FFT and displays the result on an\nintensity graph. Note that the
AMA382-Operation-Research
- NA, it is only for test
ras
- Rasapi32 usado na dll Rasapi32.d-Rasapi32 usado na dll Rasapi32.dll
matlabPBG
- matlab透射率随入射角变化的程序 na=2.10 nb=1.46 n1=1 n2=1 d=1064 for c5=0:0.5:90 c3=c5*pi/180 c1=asin(n1*sin(c3)/na) c2=asin(na*sin(c1)/nb) c4=asin(nb*sin(c2)/n2) d1=1064 a=d1/(4*na) b=d1/(4*nb) Ba=2*pi*na*a*cos(c1)/d Bb=2*pi*nb*b*cos
G
- 一个原序列A(1),A(2),…,A(n) 在一秒后序列后将会变成 A(1),A(2)+2A(1),A(3)+2A(2)+3A(1),…,A(n)+2A(n-1)+…+nA(1) 求在T秒后的序列。-One of the original sequence A (1), A (2), ..., A (n) in the second after the sequence will become A (1), A (2)+2A (1), A (3)+2A (2 )+3A (1), ..
10_0102018_Gabriel
- Esse é um programa que fiz para a disciplina de Projeto e Análise de Algoritmos na Universidade de Brasília
chenyue
- 数值分析，有八个不同的源代码，是做题的时候柳下的，共大家分享-NA src
Ch04
- 概率论的分类方法。实例：使用朴素贝叶斯分类器从个人广告中获取区域倾向-Classifying with probability theory: naï ve Bayes
v5.0
- 发卡平台，非常好用，亲自试用过，好的很呐！-Issuing platform, very easy to use, personally tried, very good na!
yitlong
- 传奇一条龙网站喜欢的拿去，非常适合开一条龙的朋友。-chuan qi yi tiao long wang zhan xi huan de na qu
gui-na-suan-fa
- 有N个硬币（N为偶数）正面朝上排成一排，每次将N-1个硬币翻过来放在原位置，不断地重复上述过程，直到最后全部硬币翻成反面朝上为止。设计程序让计算机把翻币的最简过程以及翻币次数输出（用*表示正面，O表示反面）-Have a coin N (N is even) heads in a row, each time will be N- 1 coin flipped over in the original position, repeat the above process, until (till
BENDER0129
- Erich Bender Mass moments and graph chart AERO 463/464 Senior Project Mass Moments of Inertia and Stability Chart Reference frame: The moments of inertia will be calculated along a body frame with: - x pointing in the RAM directio