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fluid.editor.alpha
- The fluid editor is a prototype source code editor supporting a \"bring from\" exploration model.With the fluid editor programmers can avoid explicit navigation between source documents by incorporating related code into the document under examinatio
cup
- 银联函数,完成跨行交易之前的合法性检查，如果不满足条件则执行相应处理-UnionPay function to complete the transaction before the legitimacy of cross examination, if the conditions are not satisfied with the implementation of the corresponding processing
FileExam
- 一个期末考试统计系统，富有研究价值，希望大家下载-A statistical system at the end of the examination, the research value of rich, I hope you download
000104V7.1
- IBMAIX认证考试000-104 与大家分享一下，共进步，共勉励~~ -it s a examination called 000_104 for IBM certification! easy to learn well~ Let s share with it! Happy everyday~
networkengineercalendaryearexamanalytical2004-2009
- 网络工程师历年真题详解—清晰版,可以帮助想考网络工程师的同学们，了解历年考试重点。-Detailed network engineers over the years Zhenti- clear version, can help network engineers wanted to test the students understand the historical examination focus.
Linux-Certification
- LINUX认证。中级认证教程，LPI201 考试。祝你成功-LINUX certification. Intermediate certification tutorials, LPI201 examination. I wish you success! !
Examination-and-answers
- 有关LINUX的一些考试的试题和答案。可以通过做题加强自己LINUX的学习。补缺补差。-LINUX examination on questions and some answers. Strengthen their own problems by doing the learning LINUX. Filled making it up.
dzdz
- 查找出两个文件中具有某一相同字段的行，输入：两个文件名 如文件一是有100行的学生学号和姓名，文件二是1000行的学生学号及考试成绩 输出：二个文件 文件一为查找出的100行的学生学号及考试成绩，文件二为未查找出的900行的学生学号及考试成绩 可对原码做相应修改，来得到需要的字段，如把两个文件拼成一个，或只取其中相应字段等-Find out the two files in the same field with a line, enter: First, the two
YX956C
- 基于奇乐达方案的数码相框，实现图片的查看和一些操作-基于QT的数码相框，实现图片的查看和一些操作- Based on wonderful reaches the plan happily the digital picture frame, realizes the picture examination and some operations- based on the QT digital picture frame, realizes the picture examination and
Linux
- 《Linux系统管理》期末综合试题答案.doc，里面是三到四道上机大题的题目及指令-" The Linux system management" final comprehensive examination questions answer . Doc, which is three to four on the big questions and instructions
ProcessManager
- 1．进程的创建 编写一段程序，使用系统调用fork()创建两个子进程。当此程序运行时，在系统中有一个父进程和两个子进程活动。让每一个进程在屏幕上显示一个字符：父进程显示字符“a”；子进程分别显示字符“b”和字符“c”。试观察记录屏幕上的显示结果，并分析原因。 2．进程的控制 修改已有程序，将每个进程输出一个字符改为每个进程输出几行字符，再观察程序执行时屏幕上的现象，并分析原因。 如果在程序中使用系统调用lockf()来给每一个进程加锁，可以实现进程之间的互斥，观察并分析出现的现象
_tbl_log
- Spool Queue examination program.