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  1. bigmod

    0下载:
  2. This preview for Phill s Big Mod shows the addition of proper SUR files into the mod
  3. 所属分类:CA认证

    • 发布日期:2008-10-13
    • 文件大小:936
    • 提供者:lena
  1. RSA_algo

    0下载:
  2. this RSA algorithm which run for 1024 bits data. which have inner fuction like multiplicatin,addition,mod,power,subtaction , greater,less,equal etc .all opetaion for 1024 bit data. -this is RSA algorithm which run for 1024 bits data. which have inn
  3. 所属分类:CA program

    • 发布日期:2017-04-04
    • 文件大小:13154
    • 提供者:jitendra singh
  1. BASE64

    0下载:
  2. BASE64解码 VBS源代码 Function fDecode(sStringToDecode) Const CharList = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/" Dim iDataLength, sOutputString, iGroupInitialCharacter sStringToDecode = Replace(Replace(Replace(sSt
  3. 所属分类:CA program

    • 发布日期:2017-11-04
    • 文件大小:941
    • 提供者:aa
  1. attachments_2013_05_05

    0下载:
  2. To find mod of a number used in crypt app.
  3. 所属分类:CA program

    • 发布日期:2017-11-30
    • 文件大小:1693721
    • 提供者:Kumar
  1. 456

    1下载:
  2. RSA算法的C语言实现 1.密钥的产生 (1)选两个安全的大素数p和q。 (2)计算n=p×q,φ(n)=(p-1)(q-1),其中φ(n)是n的欧拉函数值。 (3)选一整数e,满足1<e<φ(n),且gcd(φ(n),e)=1。 (4)计算d,满足de≡1 modφ(n),即d是e在模φ(n)下的乘法逆元,因e与φ(n)互素,由模运算可知,它的乘法逆元一定存在。 (5)以{e,n}为公开钥,{d,n}为秘密钥。 2.加密 加密时首先将明文M比特串分组
  3. 所属分类:CA program

    • 发布日期:2017-03-23
    • 文件大小:1650
    • 提供者:qwerty
  1. Elgamal

    0下载:
  2. ElGamal algorithm not only used for data encryption can be used for digital signatures, their safety depends on the calculation of a finite field discrete logarithm this problem. Key to the method. First of all, choose a prime number p, the two rando
  3. 所属分类:CA program

    • 发布日期:2017-04-16
    • 文件大小:57596
    • 提供者:HamzaAnwer
  1. diffeehellmanPROGRAM

    0下载:
  2. Example 1. To find 1537 x 4248 modulo 10, you could multiply out and take the last digit, but a better way would be to replace 1537 by 7 and 4248 by 8 to start, find 7 x 8 = 56, and then take 56 mod 10 to get 6 as the answer. A handy standard no
  3. 所属分类:CA program

    • 发布日期:2017-04-25
    • 文件大小:28510
    • 提供者:pradeep
  1. RC4-Prog

    0下载:
  2. Example 1. To find 1537 x 4248 modulo 10, you could multiply out and take the last digit, but a better way would be to replace 1537 by 7 and 4248 by 8 to start, find 7 x 8 = 56, and then take 56 mod 10 to get 6 as the answer. A handy standard no
  3. 所属分类:CA program

    • 发布日期:2017-04-25
    • 文件大小:36467
    • 提供者:pradeep
  1. Yush.java.tar

    0下载:
  2. This a new algorithm in which we encrypt on the basis of position of the character. Algorithm 1 for key generation and Algorithm 2 is for encryption Algorithm A1 Step1: Let the key be ‘k’. Step2: Multiply the index number +1 with its ASCII c
  3. 所属分类:CA program

    • 发布日期:2017-04-12
    • 文件大小:878
    • 提供者:Aman Virmani
  1. prob3

    0下载:
  2. Miller-Rabin test is a primality test algorithm which determines whether a given number is prime or not. Implement Miller-Rabin primality test as given in the text book page 257, Algorithm 7.44. (aN− 1 6= 1 mod N) Write three functions to
  3. 所属分类:CA program

  1. diffie_hellman

    0下载:
  2. Implement Diffie-Hellman Key exchange protocol and demonstrate that at the end, both person will have a common Key. Do the following: 1. Set a variable p ( e.g. p = 37) and g (e.g. g = 5). 2. Generate a, a random number mod p. Now generate A,
  3. 所属分类:CA program

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