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Strassen11
- 矩阵相乘的Strassen算法，其中 乘积矩阵C = H*H，H =（hij）n*n 1. hij = ， i，j=1，…8 2. i，j=1，…12 矩阵H =（hij）n*n自动生成，取小数点后面6位计算 -Strassen matrix multiplication, the algorithm, the product matrix C = H * H, H = (hij) n * n 1. hij =, i, j = 1, ... 2. i, j = 1, ...
TriMat
- 在目录“\\上三角矩阵类的实现”中给定了文件triMat.cpp、triMat.h，请把triMat.h文件中的9个填空位置补上正确的代码，使triMat.cpp能完成上三角矩阵的加、减、乘运算。要求输入： 输入矩阵维数：4 输入矩阵a的元素（包括0）： 1 2 3 4 0 1 2 3 0 0 1 2 0 0 0 1 输入矩阵b的元素（包括0）： 1 2 3 4 0 1 2 3 0 0 1 2 0 0 0 1 -in the di
span_forest
- Computes estimates for the number of forests of a graph, input as a 0-1 incidence matrix. Notes: Compile in C++, \"g++ -o span_forest span_forest.c\". The program does not demand that the matrix is symmetric with 0 diagonal, but uses only the upper t
revmatrix
- 螺旋矩阵问题：编程产生H*L的螺旋矩阵。首先，我们用一个二维数组来放置矩阵，然后按照数字大小顺序来填充矩阵.-spiral Matrix : Programming produced H * L spiral matrix. First, we used a two-dimensional array to accommodate matrix, in accordance with the order number to filling matrix.
2
- 前两行分别指示字符矩阵的宽 w 和高 h（1<=w<=80 且 1<=h<=80）。接下来的 h 行每行 w 个字 符便是字符矩阵的内容，再下面的 1 行为要寻找的字符串的数目 n（n<10），其后的 n行便是要寻找的字符串，每个字符串不会超过 20 个字符。 -Instructions were the first two lines of wide-character matrix w and h (1 < = w < = 80 and 1 <
matrixdriver
- now, how can i call kmeans function for h , s,v separately, what parameters to be passed. here h is 512*512 matrix.and how can i construct the clustered/segmented image from the kmeans result. need sample code in matlab its urgent. Please h
juzhen
- 矩阵操作 c++实现 课程设计 #include <iostream.h> #include <stdlib.h> #include<iomanip.h> void fanzhuan1(int b[5][5]) void fanzhuan2(int b[5][5]) void juandong1(int b[5][5]) void juandong2(int b[5][5]) void print(int b[5]
LDCP
- a)Refer to the LDPC presentation slides provided, and use the input data provided below to decode the codeword Repeat a) with new matrix H, codeword and σ^2 given below-a) Refer to the LDPC presentation slides provided, and use the input data provi
rane
- 生成一个规则LDPC码的教研矩阵H,其行数(越大越好)为列数的一半-Generate a regular LDPC code research matrix H, the adults number (bigger is better) for half the number of columns
Hjz
- C语言的上H矩阵求特征值,返回值：整型。运行成功则返回1,失败则返回0(The upper H matrix of C language takes the eigenvalue and returns the value: integer.Run success returns 1, failure returns 0.)