Visual 开发 希望对你们有帮助 public static int Rom(int n, int m)//双寄或双偶 { int count = 0 //第一排Y坐标上要几个 if (n < m) { for (int i = 1 i <= n i = i + 2) { count++ } } else { for (int j = 1 j <= m j = j + 2) {

使用邻接矩阵实现图存储结构 使用邻接矩阵实现图存储结构-perform gragh ni know it

冒泡排序：从第一个元素起依次将相邻两数比较，大的调到后面，小的调到前面， 直到第n-i（第i趟排序时）个元素。-Bubble sort: successively from the first element of the adjacent two numbers compare transferred back big and small front transferred until the first ni (i-trip sort) elements.