搜索资源列表
bessel
- Individual files are available in the following links: Bessjy -- Bessel functions Jn and Yn for real argument and integer or real order. Bessik -- Modified Bessel function In and Kn for real argument and integer or real order. CBessjy -- B
Scientific_Computing_and_C_assembly
- 第二章 解线性方程组的直接法 第三章 解线性方程的迭代法 第四章 插值法 第五章 数据拟合 第六章 数值微分和积分 第七章 矩阵特征值问题 第八章 非线性方程数值解法 第九章 非线性方程组的抚今迭代解法 第十章 常微分方程初值问题的数值解法 第十一章 常微分方程边值问题的数值解法 附录A C语言屏幕绘图 -Chapter II solution of linear equations in Chapter III of the direct meth
FDTD-IV
- THE FINITE-DIFFERENCE TIME-DOMAIN (FDTD) PART IV The Perfectly Matched Layer (PML) Absorbing Boundary Condition -THE FINITE-DIFFERENCE TIME-DOMAIN (FDTD) PART IV The Perfectly Matched Layer (PML) Absorbing Boundary Condition
sap4
- 有限元程序源程序,sap iv, 其后续版本已发展为商业软件sap2-Program: SAP IV Title: Static and Dynamic Response of Linear Systems Developer: K-J. Bathe, E.L. Wilson and F. E. Peterson, Department of Civil Engineering, University of California, Berkeley 1
Adaptive_Beamforming
- Consider a BPSK transmitter, in an unknown direction, emitting signal continuously. An interfering device (jammer) is also transmitting continuously a tone of the same frequency as that of BPSK transmitter. Following cases are of interest: Case
ALGORITHMS-FOR-NUMERICAL-ANALYSIS-IN-HIGH-DIMENSI
- Nearly every numerical analysis algorithm has computational complexity that scales exponentially in the underlying physical dimension. The separated representation, introduced previously, allows many operations to be performed with scaling that i
CH4
- 数值计算方法,fortran语言版,第四章非线性方程(组)求解-Numerical methods, the FORTRAN version, Chapter IV non-linear equation (s) for solving
turn-albo-to-ruma-data
- 输入一个不确定位数的数字,将其转化罗马数字,用"X","I","II","III","IV","V","VI","VII","VIII","IX"代表0,1,2,3,4,5,6,7,8,9的罗马数字。 程序不是太严谨,和实际的表示(10应该用X表示,五十用C表示等等)也有差距。受定义类型的限制,位数不能无限多。 程序共用了三种方法,注释掉的是两种麻烦并且占内存多(其实可以修改成和第一种方法占内存一样多)的方法-Enter an uncertain number of digits,
4
- 1、定义一个复数类,要求包括 i、无参构造函数,初始化实部和虚部均为0 ii、有参构造函数,通过参数初始化实部和虚部 iii、输出复数的成员函数 iv、以成员函数的方式重载复数加法 v、以友元的方式重载复数加法 2、三维数据型如a+bi+cj(其中abc为实数),加法法则为 (a1+b1i+c1j)+(a2+b2i+c2j)=(a1+a2)+(b1+b2)i+(c1+c2)j 要求 i、以题目1的复数为基础,采用继承的方式构造三维数据类(包括无参和有参构造函数
