我们解决八数码问题,广度优先搜索可能会导致内存不够用,采用启发式搜索,启发函数为f(x)=g(x)+h(x) g(x)为该结点不同于目标结点的个数,h(x)为该结点的深度,选择那f(x)结点最小的那个结点进行扩展, 引入了一个\"扩展数组[4]\"(因为扩展的结点最多只有4个),该数组保存着某个结点的0点向各个方向的扩展的结点对象,然后对该扩展数组进行分析,利用启发函数在进行递归扩展... -us solve eight digital, BFS may lead to insufficient

我们解决八数码问题,广度优先搜索可能会导致内存不够用,采用启发式搜索,启发函数为f(x)=g(x)+h(x) g(x)为该结点不同于目标结点的个数,h(x)为该结点的深度,选择那f(x)结点最小的那个结点进行扩展, 引入了一个\"扩展数组[4]\"(因为扩展的结点最多只有4个),该数组保存着某个结点的0点向各个方向的扩展的结点对象,然后对该扩展数组进行分析,利用启发函数在进行递归扩展... -us solve eight digital, BFS may lead to insufficient

Heapsort 1.A heap is a binary tree satisfying the followingconditions: -This tree is completely balanced. -If the height of this binary tree is h, then leaves can be at level h or level h-1. -All leaves at level h are as far to the left as po

H网联想记忆12*11阵列存储8个数字，打乱后重新记忆起-H network associative memory array 12* 11 store up to 8 digital memory , disrupting the re- starting

环境为winpython 32bit 2.7.5.3 p = PCA() print u"均值化后的数据集为：",p.dataset( H:\\PCA_test.txt ) print u"协方差矩阵为：",p.COV() print u"特征向量为：",p.eig_vector()[1] tt = p.pc(dim=1) print "tt:",tt print u"新的维度数据集",tt[1]- """ Principal c