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buhao7-1
- .data val1 sword 0 val sword -276 .code main proc mov ax,val cwd mov bx,10 idiv bx mov val1,ax call writebin call crlf mov ax,dx call writebin exit main endp end main
ajax2
- ajax学习 ajax学习 ajax学习 ajax学习 ajax学习 ajax学习 ajax学习 ajax学习 ajax学习 ajax学习 ajax学习-ajax learning a jax learning a jax learning a jax learning a jax learning a jax learning a jax Learning ajax learning ajax learning ajax learning ajax learning ajax learning
PrtInt16
- 十进制打印AX寄存器中的值的函数 对64位数的高32位进行递归排序-metric Print AX register with the value of the function of the median 64-32 ranking for recursive
filesys
- 自主开发的文件系统，自由协议 调用 mov ax,600 mov [7e20h],ax mov al, A mov [7f00h],al mov al,0 文件名以数字0结束 mov [7f01h,al 本例中文件数据位于内存 0000:2000h mov ax,cs mov ds,ax mov ax,7600h jmp ax
闰年计算
- data segment ;定义数据段 infon db 0dh,0ah,'Please input a year: $' Y db 0dh,0ah,'This is a leap year! $' N db 0dh,0ah,'This is not a leap year! $' w dw
Administrator
- DAC0832输出的是电流，要转换为电压，还必须经过一个外接的运算放大器，实验线路如图所示。-dat segment import db input a 4 bit hex:$ output db the equal number=$ err db wrong number$ dat ends cod segment assume cs:cod,ds:dat start: mo
9999
- 汇编语言画圆,计算三角形水平边平方,●双字减法，入口参量：bx减数的低16位，cx减数的高16位，dx被减数高16位，ax被减数低16位-Assembly Language Circle, calculate the square side of the triangle level, ● double-word subtraction, import parameters: bx subtrahend the low 16, cx subtrahend high 16, dx minuend
youyi
- 汇编实验用来实现dx,ax寄存器中存储数据双字右移-Used for the compilation of experimental dx, ax register to store data in two-word shifted to right,
asm
- 编程实现双字数据右移。 试写出程序将DX,AX中的双字右移四位。 -Programming shifted to right double-word data. Try to write program DX, AX shifted to right in the four pairs of characters.
AXregisterdividedintofourgroupsof16bits
- 编写一个程序，将AX寄存器中的16位数分成四组，每组四位，然后把这四组数分别放在AL,BL,CL,DL中。-Write a program, the AX register in the 16-digit divided into four groups, each with four, and then put these four groups, respectively AL, BL, CL, DL in.
divideoverflow
- 设AX/BL，当BL=0时产生除数为零中断，编写除数为零中断处理程序，显示DIVIDED BY ZERO！-Set AX/BL, while BL = 0 division by zero interrupt generated when the preparation of the division by zero interrupt handler, display DIVIDED BY ZERO!
12computer
- 书后作业题目答案。将ax寄存器中的16为数分成四组，每组4位，分别放在al ，bl ，cl，dl中-the answer
AX=b
- 已知线性方程组，求解，得到一个结果向量。-Known linear equations, solving, we obtain a result vector.
7
- 将AX寄存器中的16位数分成4组，每组4位，然后把这四组数分别放在AL、BL、CL和DL中-AX register will be divided into 4 groups of 16 bits, each 4-bit, and then put these four groups, respectively AL, BL, CL, and DL in
M45
- 编写一程序，要求计算ax寄存器中1的个数-Write a procedure that requires the calculation of the number of ax register 1
Recycling
- 编程计算以下8个数据的和，结果存放在ax寄存器中： 0123h,0456h,0789h,0abch,0defh,0fedh,ocbah,0987h-Computes the following 8 data, and results in ax register: 0123h,0456h,0789h,0abch,0defh,0fedh,ocbah,0987h
grouping
- 将AX寄存器中的16位数分为4组，每组4位，然后把这四位数分别放在AL,BL,CL,DL中-Will the register AX 16 digit is divided into four groups of four, then put these four digits were in AL, BL, CL, DL
3
- 用轻松汇编调试汇编语言例子（求双字DX:AX中的1的个数）-Easy assembly with debugging assembly language example (find double word DX: AX in the number of 1)
masm
- win32 汇编语言 播放歌曲的小程序 完整 STACK SEGMENT DB 200 DUP ( STACK ) STACK ENDS CODE SEGMENT ASSUME DS:DATA,SS:STACK,CS:CODE START: MOV AX,DATA MOV DS,AX MOV aH, 0 MOV AL,00 INT 10H ********** 定义一个宏显示 waitf proc near
masm-query
- 汇编实现字符查找功能:data segment word1 db macth! ,0ah,0dh, $ word2 db no match! ,0ah,0dh, $ buffer1 db ? 存入关键字 buffer2 db 20h dup(?) db 0 db 20h duo(?) 存输入字符，大小可改 data ends stack1 segment stack db 200h dup(?) stack1 ends code se