搜索资源列表
25_GONG
- 列句25宫的所有组合。 每行,每列,和对角线 数字和为25。-sentence of 25 out of all the combinations Palace. Each line, each and diagonal figures and 25.
1800Decorations
- 该源码是一个问题的解决方法。问题是给你个长为L的串，串中可以出现n种字符，还给出m个子串，求有多少个长为n的只由这些字串组成的串。输入例子：4 5 6 ABB BCA BCD CAB CDD DDA 结果为2.而5 4 5 E D C B A的结果为625-source of the problem is a solution. The problem is that you have the head of the L series, the series can occur n ch
MicrosoftWord2
- y_compare= 1.0954 1.1832 1.2649 1.3416 1.4142 1.4833 1.5492 1.6125 1.6734 1.7321 1.0954 1.1832 1.2649 1.3416 1.4142 1.4832 1.5492 1.6125 1.6733 1.7321 var_y=2.1742e-010 精度再上一个层次(三阶代数精度) -y_compare = 1.0954 1.1832 1.2649 1.3416 1. 4142 1.48
testcon
- 一个数学模型的优化 function testcon() ％％ 设置初始值，上下限； x0=[18 13 11] lb=[3 0.1 7] ub=[25 1 25] ％％ 调用优化求解函数(testcon)
Project
- C 语言开发的日历（课程设计很不错的） Month:123/1 --- --- --- Sun Mon Tue Wed Thu Fri Sat 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31
Gauss-Seidel
- Using Jacobi method and Gauss-Seidel iterative methods to solve the following system The required precision is =0.00001, and the maximum iteration number N=25. Compare the number of iterations and the convergence of these two me
Gaussian_row
- We can see that using Gauss-Seidel iterative methods need only 13 timed to make But using Jacobi method after 25 times the is bigger than that
mathvalue_1
- 从人口普查统计，已知某国新生儿母亲的年龄累计分布为N=N(t)，其中t为母亲年龄，N为新生儿的母亲年龄低于或等于t的新生儿数目。下表给出了间距为5的数据。 t 15 20 25 30 35 40 45 50 N 0 7442 26703 41635 49785 50209 50226 50230 取边界条件为N’(15)=N’(50)=0,利用三次样条插值求出15至50岁之间，每一年龄（即x=15,16,……，50）所对应的新生儿累计数目N，并绘出插值函数的图形。
power
- 幂法: 程序中把循环变量定义为循环20次，同样可以更改 示例 矩阵: 1.0 1.0 0.5 1.0 1.0 0.25 0.5 0.25 2.0 初值(1 1 1)T
th
- 弹簧隔振器的系数k0=4.5 hc=3.5 d=[3.15 3.23] a1=tan(pi*(d)./(2*hc)) a2=cot(pi*(d)./(2*hc)) ％ plot(d,a1) y=(a1+a2)*2*k0*hc*1e-3./pi y=y./9.8*8 ％ var=1+(tan(pi*(d+0.25)./(2*hc))).^2 k=2*k0*hc/pi*( var*pi./(2*hc)+var*pi./(2*hc)./
gaojingdu.c
- 高精度幂，底输入0.0到99.999；幂输入0-25。性能超群。
homework3
- 离散事件系统仿真程序CPU_scheduler说明： 1.仿真功能与要求： 1.1 单CPU系统，系统有10个终端输入任务，如果一个任务的执行时间大于规定的时间片，则该任务执行一个时间片之后退出CPU，并重新参加排队，直到执行完退出CPU，然后才允许相应终端重新输入一个新的作业。任务排队的原则是在CPU中执行次数越少的越排在前面，如果两个任务执行的次数相同，按照FIFO原则排队。 1.2 每个终端输入任务的时间满足均值为25秒的指数分布。每个任务需要CPU执行的时间满足均值
计算几何
- 目录 ㈠ 点的基本运算 1. 平面上两点之间距离 1 2. 判断两点是否重合 1 3. 矢量叉乘 1 4. 矢量点乘 2 5. 判断点是否在线段上 2 6. 求一点饶某点旋转后的坐标 2 7. 求矢量夹角 2 ㈡ 线段及直线的基本运算 1. 点与线段的关系 3 2. 求点到线段所在直线垂线的垂足 4 3. 点到线段的最近点 4 4. 点到线段所在直线的距离 4 5. 点到折线集的最近距离 4 6. 判断圆是否在多边形内 5
fuliyejishu
- 创建25个谐波的傅立叶级数，计算三角形式的傅立叶级数并将计算结果和转换结果相比较，最后绘制频谱。-The creation of 25 harmonic Fourier series, calculation of the triangular form of Fourier series and the results of calculations and conversions, compared to the final rendering spectrum.
cs559-25
- 解说B样条插值的使用，有曲线和曲面，在国外网站上下载的，很好-Explain the use of B-spline interpolation, there are curves and surfaces, in foreign Web site to download, very good
Jacobidiedai
- 用雅克比迭代法解下列方程组 10x1-x2+2x3=-11 8x2-x3+3x4=-11 2x1-x2+10x3=6 -x1+3x2-x3+11x4=25-Jacobi iterative method with the solution of the following equations 10x1-x2+2 x3 =- 11 8x2-x3+3 x4 =- 11 2x1-x2+10 x3 = 6-x1+3 x2-x3+11 x4 = 25
GaussSeideldiedai
- 高斯—赛德尔迭代法解下列方程组 10x1-x2+2x3=-11 8x2-x3+3x4=-11 2x1-x2+10x3=6 -x1+3x2-x3+11x4=25-Gauss- Seidel iterative solution of the following equations 10x1-x2+2 x3 =- 11 8x2-x3+3 x4 =- 11 2x1-x2+10 x3 = 6-x1+3 x2-x3+11 x4 = 25
spline_VB
- 三次样条函数 Type coordinateX Y x As Double y As Double End Type Public Const dotSize = 25 Public Const H = 4000 Public Const W = 4-Cubic Spline
Character-Frequency-Analysis-of-Bosnian
- In this project I chose Bosnian language to do the character frequency analysis. Bosnia and Herzegovina are the countries using Bosnian as their official language and more than 2.2 million people speak this language all around the world. It has 5
GL-25
- 基于新的交叉算子的全局与局部实数编码遗传算法GL-25-Global and local real-coded genetic algorithms based on parent-centric crossover operators