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fet440_adc12_06
- This example shows how to perform a repeated sequence of conversions using // \"repeat sequence-of-channels\" mode.
hyplas
- ************************************************************************ * * * * * THIS IS THE H Y P L A S 2.0 README FILE * * ----------------- * * * * HYPLAS is a finite element program for implicit small and large * * strain analisys of hyperelast
kmean
- k-means 算法的工作过程说明如下：首先从n个数据对象任意选择 k 个对象作为初始聚类中心；而对于所剩下其它对象，则根据它们与这些聚类中心的相似度（距离），分别将它们分配给与其最相似的（聚类中心所代表的）聚类；然后再计算每个所获新聚类的聚类中心（该聚类中所有对象的均值）；不断重复这一过程直到标准测度函数开始收敛为止。-k-means algorithm process as follows: First of all, the object data from the n choose k
zuixiaoerchengdiedai
- 这是最小二乘迭代算法，能够实现匹配时的同名点反复迭代，提高匹配精度-This is the least-squares iterative algorithm that can achieve the same title match point when repeated iteration to improve the matching accuracy
thesis2002_zhangyifei
- 张一飞论文 人们认识事物的过程中，开始只是看到了各个事物的现象。这就是认识的感性阶段。在这个阶段中，还不能作出合乎逻辑的结论。 随着研究的深入，这些感觉和印象的东西反复了多次，于是在人们的脑子里生起了一个认识过程中的突变，最后产生出合乎逻辑的结论。这就是认识的理性阶段。-Zhang Yi-fei paper learn about the things people in the process of the beginning of all things just to see
arrange1
- 有重复元素的排列问题，有重复元素的排列问题-Overlapping elements alignment problem, there are repeated elements in the arrangement of the problem
Monte_Carlo_simulation_cool
- 蒙特卡罗模拟随机数是最好的方式，本程序设计在552nm脉冲后，再一左一右的657nm冷却脉冲，测试激发达到100 的概率，尤其考查蓝、绿及近红外波段-MATLAB 6.5 Monte Carlo simulation cool3.m This simulation cycles "num" number of atoms "steps" times, with a cooling sequence of a 657 nm cooling pulse from the right, the
WindowsApplicationHangshu
- 这是用C#写的有关实现多维回归方程的程序，是多元一次的回归方程，如果是多次多元也可以转化为多元一次这一类来实现～-It is written in C# for the realization of multi-dimensional regression equation procedure is a multiple regression equation, if it is repeated multiple can be turned into this kind of first to
matlab2
- 数值分析计算实习题.复化梯形求积.复化辛普森求积.自适应步长辛普森求积.龙贝格函数求积.-Practical numerical analysis problems. Repeated trapezoidal quadrature. The Simpson quadrature. Adaptive Simpson Quadrature step. Romberg Quadrature functions.
Josephus
- 已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。 -Known n individuals (in numbers 1,2,3 ... n respectively) sitting around a round table around. From the number of people began to report the numbe
Calc
- 四则运算计算器 可以计算整数四则运算，例如：7+5*(3+4) (1)按要求在提供的框架程序源程序的基础上对程序进行修改、补充，并调试通过。 (2)修改主程序结构，使程序可以反复运算，直到选择退出为止。 (3)增加文件的输入输出功能，是计算过的式子和结果可以根据需要设置命令存储到文件中，同时也可以直接从文件中输入四则运算的式子，运算后，结果输出到原文件中。-Arithmetic calculator can calculate the integer arithme
Non-Repeated_Random_Generator
- It s a code that can generates a set of random numbers without being repeated
a-new-Least-squares-fitting-method
- 本程序是基于非等距节点的正交多项式的最小二乘法拟合算法，该算法已经在vc++6.0下调试通过，经多次验证，本算法的拟合误差较小。-This procedure is based on equidistant nodes of non-orthogonal polynomial least squares fit algorithm, which has been in vc++6.0 through debugging, after repeated verification, the algo
Matrix-multiplication-problems-with
- 给定n个矩阵{A1,A2,…,An}，其中Ai与Ai+1是可乘的，i=1,2,…,n-1。要算出这n个矩阵的连乘积A1A2…An。由于矩阵乘法满足结合律，故计算矩阵的连乘积可以有许多不同的计算次序。这种计算次序可以用加括号的方式来确定。若一个矩阵连乘积的计算次序完全确定，也就是说该连乘积已完全加括号，则可以依此次序反复调用2个矩阵相乘的标准算法计算出矩阵连乘积。本文的功能是采用动态规划算法，给出矩阵的一种最优的加括号方式，是计算量最小。-Given n matrices {A1, A2, ...
BigInt_cpp
- 本程序的编写思路是，把所有输入的数字当作字符串进行处理，进行强制转换成整形数据，然后模仿笔算方法，对整形数据进行处理，最后得到的数据，再次转换成字符串类型，并存储输出。本程序运行速度快、功能强，是作者于完成应用密码学课程设计时编写而成的，经反复测试无误。-The procedures for the preparation ideas, the number of all input as string processing, cast into plastic data, and then i
3-prime-check
- 利用模重复平方实现费马特素性检验，范围在四万之内就行。-Model repeated square Fei Mate primality test, the range of forty thousand of the line.
3-prime-check2
- 利用模重复平方实现费马特素性检验，范围在四万之内，纠正了一些小数值的错误。-Model repeated square Fei Mate primality test, the range of forty thousand of the corrected some small numerical errors.
Calcutor
- 可以实现连续计算的MFC计算器VC6.0编译-A simple calculator which can repeated calculate.It is compiled by VC++ 6.0 MFC
repeated-measures-ANOVA
- 用MATLAB实现单因素/两因素重复测量方差分析，自带工具包中只有非重复测量的方差分析函数ANOVA。anova_rm实现单因素；rm_anova2实现两因素- function stats = rm_anova2(Y,S,F1,F2,FACTNAMES) Two-factor, within-subject repeated measures ANOVA.For designs with two within-subject factors. function [p, table] =
Longest-repeated-substring
- 一个计算字符串中最长重复子串的算法，开发语言是C/C-A string of the longest repeated substring algorithm development of language is C/C++